Answer:
[tex]C)~ 7[/tex]
Step-by-step explanation:
[tex]\text{Given that,}~~ (x_1,y_1) = (k,3)~ \text{and}~ (x_2 ,y_2) = (2,3)\\\\\text{Distance,}~ \\\\~~~~~~~~d= \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}\\\\\implies 5=\sqrt{(2-k)^2 + (3-3)^2}\\\\\implies 5=\sqrt{(2-k)^2 +0}\\\\\implies 5 = \sqrt{(2-k)^2}\\\\\implies 5=|2-k|\\\\\implies \pm 5=2-k \\\\\implies 2-k =5~~~~~~\text{or}~~~~~~~~2-k = -5\\\\\implies k = 2-5~~~~~~\text{or}~~~~~~~~k = 2+5\\\\\implies k = -3~~~~~~~~~\text{or}~~~~~~~~k = 7[/tex]
