can someone help me with this problem please? Thank you!

Answer:
[tex]\boxed{\small\text{SA = 106 cm}^{2}}[/tex]
Step-by-step explanation:
The surface area of the net shown is the sum of the area of it's faces. We can tell that the net includes two triangles and three rectangles. Therefore,
[tex]\implies \small\text{SA = A (Rectangle 1) + A (Rectangle 2) + A (Rectangle 3) + \text{A (Triangle 1) + A (Triangle 2)}}[/tex]
Note: Refer to image
A (Rectangle 1):
Area of rectangle = Length × Width
⇒ = 7 × 5
⇒ = 35 cm²
A (Rectangle 2):
Area of rectangle = Length × Width
⇒ = 7 × 5
⇒ = 35 cm²
A (Rectangle 3):
Area of rectangle = Length × Width
⇒ = 3 × 7
⇒ = 21 cm²
A (Triangle 1):
Area of triangle = 1/2 × Base × Height
⇒ = 1/2 × 3 × 5
⇒ = 1/2 × 15
⇒ = 7.5 cm²
A (Triangle 2):
Area of triangle = 1/2 × Base × Height
⇒ = 1/2 × 3 × 5
⇒ = 1/2 × 15
⇒ = 7.5 cm²
Therefore, the surface area;
[tex]\implies \small\text{SA = 35 + 35 + 21 + 7.5 + 7.5}}[/tex]
[tex]\implies \small\text{SA = 70 + 21 + 15}}[/tex]
[tex]\implies \boxed{\small\text{SA = 106 cm}^{2}}[/tex]