can someone help me with this problem please? Thank you!

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Answer :

Answer:

[tex]\boxed{\small\text{SA = 106 cm}^{2}}[/tex]

Step-by-step explanation:

The surface area of the net shown is the sum of the area of it's faces. We can tell that the net includes two triangles and three rectangles. Therefore,

[tex]\implies \small\text{SA = A (Rectangle 1) + A (Rectangle 2) + A (Rectangle 3) + \text{A (Triangle 1) + A (Triangle 2)}}[/tex]

Note: Refer to image

A (Rectangle 1):

Area of rectangle = Length × Width

⇒                           = 7 × 5

⇒                           = 35 cm²

A (Rectangle 2):

Area of rectangle = Length × Width

⇒                           = 7 × 5

⇒                           = 35 cm²

A (Rectangle 3):

Area of rectangle = Length × Width

⇒                           = 3 × 7

⇒                           = 21 cm²

A (Triangle 1):

Area of triangle = 1/2 × Base × Height

⇒                        = 1/2 × 3 × 5

⇒                        = 1/2 × 15

⇒                        = 7.5 cm²

A (Triangle 2):

Area of triangle = 1/2 × Base × Height

⇒                        = 1/2 × 3 × 5

⇒                        = 1/2 × 15

⇒                        = 7.5 cm²

Therefore, the surface area;

[tex]\implies \small\text{SA = 35 + 35 + 21 + 7.5 + 7.5}}[/tex]

[tex]\implies \small\text{SA = 70 + 21 + 15}}[/tex]

[tex]\implies \boxed{\small\text{SA = 106 cm}^{2}}[/tex]

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