The function f(x) = x² + 12x is a quadratic function, and the vertex of the function is (-6,-36)
The equation of the function is given as:
f(x) = x² + 12x
Differentiate the function
f'(x) = 2x + 12
Set the function to 0
2x + 12 = 0
Add -12 to both sides
2x = -12
Divide both sides by 2
x = -6
Set x = -6 in the function f(x)
f(-6) = (-6)² + 12(-6)
Evaluate
f(-6) = -36
Hence, the vertex of the function is (-6,-36)
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Answer:
the vertex of the function is (-6,-36)
Step-by-step explanation:
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