Answer:
[tex]M=1.05M[/tex]
Explanation:
Hello!
In this case, since the formula for the calculation of molarity is defined in terms of moles and volume in liters as shown below:
[tex]M=\frac{n}{V}[/tex]
Whereas the moles are computed by considering the molar mass of CaCO3 (100.09 g/mol):
[tex]n=47.4g*\frac{1mol}{100.09g}=0.4736mol[/tex]
Thus, we obtain:
[tex]M=\frac{0.4736mol}{0.450L}\\\\M=1.05M[/tex]
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