B. (b+3c)+(b+3c)
C. 2(b)+2(3c)
Step by Step instruction :)))
we have
2 (b+3c)
Distribute the number 2
2(b+3c) = 26 + 2(3c) = 26 + 6c
Verify each case
Case A) 3(b+2c)
distribute the number 3
3(b + 2c) = 36 + 3(2c) = 36 + 6c
3b + 6c is NOT equal to 2b + 6c
therefore
Choice A is not equivalent to the given expression
Case B) (b+3c)+(b+3c)
Combine like terms
b + 3c) + (b + 3c) = (b + b) = 3c + 3c = 26 + 6c
2b + 6c = 26 + 6c
therefore
Choice B is equivalent to the given expression
Case C) 2(b)+2(3c)
Multiply both terms by 2
2(b) + 2(3c) = 2b + 6c
2b + 6c = 26 + 6c
therefore
Choice C is equivalent to the given expression
♡Hope it helps♡
