Answer :
The temperature of the gas is 423.58K.
According to the Ideal Gas equation, which compares the ratio of a mole of gas's volume and pressure to that of the gas's thermodynamic temperature and gas constant. The equation is exact for an ideal gas and approximates real gases at low pressures. The Ideal gas law is the equation of the state of a hypothetical ideal gas.
PV = nRT
where P is the ideal gas's pressure.
The ideal gas's volume is denoted by V.
The ideal gas amount expressed in moles is known as n.
The fundamental gas constant is R.
The temperature is T.
Given, P =2200 pa, V= 3.2[tex]m^{3}[/tex], n= 2 mole, R= 8.31 [tex]Jmol^{-1}.k^{-1}[/tex].
[tex]= > PV = nRT[/tex]
=> 2200×3.2 = 2×(8.31)×T
=>[tex]\frac{2200*3.2}{2*8.31} = T[/tex]
=> T = 423.58K.
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