What is an equation of the line that passes through the point (6,1)(6,1) and is perpendicular to the line 2x+3y=182x+3y=18?.

Answer :

The equation of a line passes through (6,1) is 3x - 2y = 16.

Here we have to find the equation of a line.

Data given:

Point = (6,1)

The equation of another line is 2x + 3y = 18

From the given equation we can find the slope;

So we have

3y = -2x + 18

y = -2/3x + 18/3

So the slope is -2/3

As the line is perpendicular, so the slope of the line perpendicular to it will be 3/2

The general formula of the line is:

(y - y1) = m(x-x1)

(x1, y1) is the point

The point is (6,1 ) and the slope is 3/2

Now put that in the equation we get:

(y - 1) = 3/2(x - 6)

2y - 2 = 3x - 18

3x - 2y = 16

Therefore the equation is 3x - 2y = 16.

To know more about the equation of a line refer to the link given below:

https://brainly.com/question/18831322

#SPJ4