A 6. 0-m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 hz, the wavelength is 0. 40 m, and the amplitude is 4. 0 mm, is propagating on the wire. The time for a crest of this wave to travel the length of the wire is closest to.

Answer :

The time for the crest of a wave having a frequency of 810 hz, a wavelength of 0.40 m, and an amplitude of 4.0 mm to travel to the closest length of wire is 19 ms.

Wavelength

Wavelength is the distance between one wave frequency peak and another peak. Therefore, the wavelength of frequency is the distance that a wave must travel in one period. This wavelength is denoted by the symbol λ (lambda) with units of m (meters).

the equation between wavelength, speed and frequency is:

λ = v/f

We have,

Wavelength = 0.4 m  ⇒ λ

Frequency = 810 hz ⇒ f

Distance = 6.0 m

And, the velocity:

v = λ x f

= (0.4) (810)

= 324 m/s

So, the time for a crest of this wave to travel the length of the wire is closest to:

time = distance/velocity

= 6/324

= 0.0185 s = 19 ms.

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