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A 65-kg swimmer pushes on the pool wall and accelerates at 6 m/s^2. The friction experienced by the swimmer is 100 n. What is the magnitude of the force that the swimmer applies on the wall?.

Answer :

For a 65-kg swimmer to push against the pool wall, there is a force of 490N applied, and the swimmer accelerates at a speed of 6 m/s2. The swimmer encounters 100 n of friction.

According to Newton's second law,

sum Force = mass × acceleration

Fm - Ff = ma

Fm is the moving force

If s the frictional force = 100N

mass = 65kg

acceleration = 6m/s²

Required

Moving force Fm

Substitute the given force into the expression and get Fm

Fm -100 = 65(6)

Fm -100 = 390

Fm = 390+100

Fm = 490N

Hence the force that will cause two carts to move is 490N.

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