What are the vertex and range of y = |x − 5| 4? (5, 4); −[infinity] < y < [infinity] (5, 4); 4 ≤ y < [infinity] (−5, 4); −[infinity] < y < [infinity] (−5, 4); 4 ≤ y < [infinity]

Answer :

The range and the vertex is   4 ≤ y < [infinity] and  (5, 4).

To find the vertex, we can take the derivative of the function and set it equal to 0:

y' = |x − 5|' = 0

=> x − 5 = 0

=>  x = 5

Then, we can plug x = 5 into the original equation to find the y-value at the vertex:  

y = |x − 5| = |5 − 5| = |0| = 0

So, the vertex of y = |x − 5| is (5, 4).

To find the range, we need to consider the range of the absolute value function. The range of the absolute value function is:

−[infinity] < y < [infinity]. So, the range of y = |x − 5| is also −[infinity] < y < [infinity] (or 4 ≤ y < [infinity]).

To know more about the range refer to  the link   brainly.com/question/28135761

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