Answered

Halla el menor de tres enteros impares consecutivos tales que 7 veces el entero del medio sea 15 más que la suma del primero y tercer enteros.

Answer :

Using an algebraic equation to represent the word problem, the smallest integer is 1

Word Problem

This is a way of representing mathematical problems with words. To solve this, we have to use algebraic equations or expressions.

Let the integers be represented as

  • x
  • x + 2
  • x + 4

We can write an equation from the word problem given as

7 × (x + 2) = 15 + [x + (x + 4)]

7x + 14 = 15 + x + x + 4

7x + 14 = 15 + 2x + 4

collect like terms

7x - 2x = 15 - 14 + 4

5x = 5

Divide both sides by coefficient of x

5x / 5  = 5 / 5

x = 1

The smallest integer is 1

Learn more on word problem here;

https://brainly.com/question/13818690

#SPJ1

Translation:

Find the smallest of three consecutive odd integers such that 7 times the middle integer is 15 more than the sum of the first and third integers

Go Question: Other Questions