Answer :
The mass of 22.4 L of gas at STP is calculated by the moles multiplied by the molar mass. and is equal to the molar mass of the gas.
According to the ideal gas equation , the expression is given as :
P V = n R T
n = P V / R T
pressure P is 1 atm
The volume V is 22.4 L
the gas constant R is 0.0823 at L / mol K
the temperature is 273 K
so, the number of moles at STP is given as :
n = P V / R T
n = ( 1 × 22.4 ) / ( 0.0823 × 273 )
n = 1 mole
the number of moles is given as :
moles = mass / molar mass
mass = moles × molar mass
mass = 1 mol × molar mass in g /mol
mass = molar mass in g /mol
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