A banked circular highway curve is designed for traffic moving at 95 km/h. The radius of the curve is 210 m. Traffic is moving along the highway at 52 km/h on a stormy day. (a) What is the mir num coefficient of friction between tires and road tb. will allow cars to negotiate the turn without sliding, (o) With this value of the coefficient of friction, what is the greatest speed at which the curve can be negotiated without sliding?

Answer :

To determine the minimum coefficient of friction that allows a car to pass a corner without skidding, you can use the following formula:

μ = v^2 / rg

where μ is the coefficient of friction, v is the speed of the car, r is the radius of the curve, and g is the acceleration due to gravity (9.81 m/s²).

Inserting the given value will result in:

μ = (52 km/h)²/ (210 m)(9.81 m/s²)

Converting the velocity to m/s and calculating it gives:

μ = 0.312

Therefore, 0.312 is the lowest coefficient of friction that a car can go through a curve without slipping.

To determine the maximum velocity that can be passed through a curve without slipping, we can use the same equation and solve for v.

v = √(μrg)

Plugging in the given values ​​and the calculated minimum coefficient of friction, we get:

v = √(0.312 × 210m × 9.81m/)

The calculation yields:

v = 60.4 km/h

The maximum speed that can be taken through a curve without slipping is 60.4 km/h.

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