The equation that can be used to solve the problem is 2 [tex] \frac{1}{3} [/tex] + c = 8 [tex] \frac{5}{6} [/tex].
Let us represent the quantity of caramel by c.
So, the sum of weights of chocolates and caramel makes up the weight of box. Hence, it will be represented as -
2 [tex] \frac{1}{3} [/tex] + c = 8 [tex] \frac{5}{6} [/tex]
Now, we will convert mixed fraction to fractions for ease of calculation.
Weight of chocolates = 2 [tex] \frac{1}{3} [/tex]
Weight of chocolates = (3×2)+1/3
Weight of chocolates = 7/3 ounces
Total weight of box = 8 [tex] \frac{5}{6} [/tex]
Total weight of box = (8×6)+5/6
Total weight of box = 53/6 ounces
Rewriting the equation now -
7/3 + c = 53/6
c = 53/6 - 7/3
Taking LCM
c = 53 - (7×2)/6
Performing multiplication on Right Hand Side of the equation
c = 53 - 14/6
Performing subtraction
c = 39/6
Converting back to mixed fraction -
c = 6 [tex] \frac{3}{6} [/tex]
Thus, the caramel weight is 6 [tex] \frac{3}{6} [/tex] ounces.
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