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the length of a rectangle is four times its width if the area of the rectangle is find its perimeter; a quadratic function g(x) passes through the points (-8, 33), (2, 1), and (8, 1).; the length of a rectangle is 4 times its width the area of the rectangle is 144 square inches; desmos; perimeter of rectangle; if the perimeter of the given triangle is subtracted by (4/a)cm , what will be its new perimeter?; the length of a rectangle is 20 units more than its width. the area of the rectangle is x4−100.; area of rectangle

Answer :

MRROYALGO

The perimeter of the rectangle 48.48 inches and the expression of the new perimeter of the rectangle is 48.48 - (1.57/a) inches

How to determine the perimeter of the rectangle

In this question, we have

Area = 144 square inches

Length = 4 * Width

The area of a rectangle is represented as

A = lw

So, we have

A = (w + 4) * w

This gives

(w + 4) * w = 144

Expand

w² + 4w = 144

So, we have

w² + 4w - 144 = 0

Using a graphing calculator, we have

w = 10.12

Recall that

l = w + 4

So, we have

l = 10.12 + 4

Evaluate

l = 14.12

The perimeter is then calculated as

P = 2 * (l + w)

So, we have

P = 2 * (10.12 + 14.12)

Evaluate

P = 48.48

So, the perimeter is 48.48 inches

The new perimeter

Here, we have

Value subtracted = (4/a) cm

Converted to inches

Value subtracted = (1.57/a) inches

So, we have

New perimeter = 48.48 - (1.57/a) inches

Read more about rectangles at

https://brainly.com/question/25292087

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Complete question

The length of a rectangle is four times its width. If the area of the rectangle is 144 square inches find its perimeter.

if the perimeter of the given rectangle is subtracted by (4/a)cm, what will be its new perimeter?;

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