Answered

the reaction of silver metal and nitric acid proceeds according to the equation below. if 0.30 mol of silver is added to 50.0 ml of 5.0 m nitric acid, how many liters of no gas can be formed at stp

Answer :

0.0625 mol of NO gas is formed at stp.

The balanced equation for the reaction is,

3Ag + 4HNO3 → 3AgNO3 + NO + 2H2O

Moles of nitric acid = 5 x 50 x 10 ^ -3 = 0.25 mol

From the shown balanced equation of reaction, 3 moles of silver react with 4 mole of HNO3

0.30 mol of Ag react with = 4/3 x 0.30 HNO3 = 0.4 mol HNO3

So, clearly HNO3 is limiting reagent. A reactant in a chemical reaction that determines the amount of product that is produced is the limiting reactant or limiting reagent.

now, 4 mol of HNO3 will give 1 mol of NO

0.25 mol of HNO3 will give = 1/4 x 0.25 mol NO

=  0.0625 moles of NO

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