the length of a rectangle is less than double the width, and the area of the rectangle is . find the dimensions of the rectangle.

Answer :

The dimensions of the rectangle are 6 and 3.5 ft.

Let the width of rectangle be x. So, the length of the rectangle will be 2x - 1. As per the known fact, the area of rectangle is given by the formula -

Area = length × breadth

Keep the values in formula to find the dimensions of the rectangle

x(2x - 1) = 21

Performing multiplication on Left Hand Side of the equation

2x² - x = 21

Rewriting the equation

2x² - x - 21 = 0

On factorizing we get, x = -3 and 3.5.

The dimensions of rectangle can not be negative, this, taking the value of x as 3.5. Now, the width of rectangle will be 3.5.

Length of rectangle = (2×3.5 - 1)

Length of rectangle = 7 - 1

Length of rectangle = 6

Thus, the length and width is 6 and 3.5 ft respectively.

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The complete question is -

the length of a rectangle 1ft less than double the width ,and the area of the rectangle is 21ft^2 find the dimensions

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