Answer :
If we assume that σ = 15 then the required sample size is 216 .
In the question ,
it is given that ,
the standard deviation is (σ) = 15
we want to be 95% confident . So , α [tex]=[/tex] 1 - 0.95 = 0.05
So , [tex]Z_{\frac{\alpha }{2} }[/tex] is = [tex]Z_{\frac{0.05 }{2} }[/tex] = Z₀.₀₂₅
from z table ,
Z₀.₀₂₅ = 1.96 .
e is given to be = 2 IQ points
the sample size (n) is calculated using the formula .
n = (σ × [tex]Z_{\frac{\alpha }{2} }[/tex]/e)²
Substituting the values ,
we get ,
n = (15 * 1.96/2)²
n = (29.4/2)²
n = (14.7)²
n = 216.09
n ≈ 216
Therefore , the sample size necessary to estimate the mean IQ score of statistics students is 216 .
The given question is incomplete , the complete question is
The standard IQ test is designed so that the mean is 100 and the standard deviation is 15 for the population of all adults. We wish to find the sample size necessary to estimate the mean IQ score of statistics students. Suppose we want to be 90% confident that our sample mean is within 2 IQ points of the true mean. Assume then that σ = 15 and determine the required sample size .
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