Answered

how fast would a(n) 73 kgkg man need to run in order to have the same kinetic energy as an 8.0 gg bullet fired at 430 m/sm/s ?

Answer :

EDUARD22SLYGO

The velocity of the 73 Kg man needed for him to have the same kinetic energy as the 8.0 g bullet fired at 430 m/s is 4.5 m/s

How do I determine the velocity of the man?

First, we shall obtain the kinetic energy of the bullet. This can be obtained as follow:

  • Mass (m) = 8 g = 8 / 1000 = 0.008 Kg
  • Velocity (v) = 430 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.008 × 430²

KE = 739.6 J

Finally, we shall determine the velocity of the 73 Kg man. Details below:

  • Mass of man (m) = 73 Kg
  • Kinetic energy (KE) = 739.6 J
  • Velocity of man (v) = ?

KE = ½mv²

739.6 = ½ × 73 × v²

739.6 = 36.5 × v²

Divide both side by 36.5

v² = 739.6 / 36.5

Take the square root of both side

v = √(739.6 / 36.5)

v = 4.5 m/s

Thus, the velocity man is 4.5 m/s

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