The possible products of the Substitution reaction of (r)-3-chloro-3-methylhexane with methanol and heat are A and D.
The substitution reaction of (r)-3-chloro-3-methylhexane with methanol and heat is a nucleophilic substitution reaction. In this reaction, the chlorine atom in (r)-3-chloro-3-methylhexane acts as the leaving group, while the methanol serves as the nucleophile. The reaction proceeds through a series of steps:
1. The chlorine atom in (r)-3-chloro-3-methylhexane is protonated by the hydrogen atom in methanol. This creates a positively charged carbon-chlorine bond.
2. The nucleophilic attack of the methanol molecule onto the positively charged carbon-chlorine bond results in the formation of a covalent bond between the two molecules.
3. The newly formed covalent bond is then broken by the removal of the chlorine atom from the molecule, leaving behind a positively charged methoxy group.
4. The positively charged methoxy group is then protonated by the hydrogen atom in methanol, resulting in the formation of a new covalent bond between the two molecules.
5. Heat is then applied to the reaction mixture, which increases the reaction rate and facilitates the formation of the desired product, (r)-3-methyl hexane-2-methanol.
This substitution reaction is an example of a nucleophilic substitution reaction, which is a type of chemical reaction in which a nucleophile (a molecule with an electron-rich center) replaces a leaving group (a molecule with an electron-poor center) from a substrate molecule.
Hence A and D are the products of the reaction. The image attached below explains Clearly the reaction.
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