Monica performed Part B of Experiment VOL and monitored the current every two minutes as instructed in Step 20. She noticed throughout the experiment the current displayed on the voltmeter repeatedly drift above the current she initially set, so every two minutes she adjusted the power supply to account for this "current drift." She uses the target current to calculate the moles of metals reduced or oxidized at the electrodes. Then determines the atomic masses of her assigned electrodes using the mass gained/lost at the electrodes and calculated moles of metal.
the current drift will [ select ] the flow of electrons. this will [ select ] the actual moles of electrons transferred from the [ select ] leading to [ select ] moles of metal reduced or oxidized at the electrodes. hence, the atomic weight will be [ select ] .
Could you help me fill in the blanks and explain why each choice is correct?

Float flow can be characterized as the charge transporter's moves in a semiconductor as a result of the electric field. There are two sorts of charge transporters in a semiconductor like openings and electrons. When the voltage is applied to a semiconductor, then, at that point, electrons push toward the +Ve terminal of a battery while the openings travel toward the - Ve terminal of a battery.

Here, openings are emphatically charged transporters though the electrons are adversely charged transporters. In this way, the electrons draw in by the +Ve terminal of a battery while the openings draw in by the - Ve terminal of a battery.

Float flow emerges from the development of transporters in light of an applied electric field. Positive transporters (openings) move in similar course as the electric field while negative transporters (electrons) move the other way. The net movement of charged particles creates a float flow that is in a similar heading as the applied electric field.

This will expand the genuine mole of electrons moved from anode to cathode prompting more moles of metal diminished or oxidized at the electrodes. Hence the nuclear weight will be possibly higher than anticipated.

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