The propagation of fatigue cracks in various aircraft parts has been the subject of extensive study in recent years. The accompanying data consists of propagation lives (flight hours/104) to reach a given crack size in fastener holes intended for use in military aircraft. 0.737 0.843 0.871 0.911 0.920 0.932 0.961 1.010 1.039 1.050 1.102 1.120 1.138 1.161 1.241 1.352 (a) Compute and compare the values of the sample mean x and median . (Round your answers to four decimal places.) x = flight hours/104 = flight hours/104 (b) By how much could the largest sample observation be decreased without affecting the value of the median? (Enter your answer to three decimal places.) flight hours/104

Answer :

On solving the provided question we got to know that, the median value won't change if the greatest sample Observation is decreased to 1.3735.

What is median?

One of three ways to gauge central tendency is the median. The center position of a record is specified when describing it. A measure of central tendency is what this is. The mean, median, and mode are the three most frequently used indicators of central tendency.

The sum of all the values is divided by the total number of values, giving the mean value.

[tex]0.736 + 0.863 + 0.865 + 0.913 + 0.915 + 0.937 + 0.983 + 1.001 + 1.011 + 1.064 + 1.109 + 1.132 + 1.140 + 1.153 + 1.253 + 1.397 = 16.472\\16.472 /16 = 1.0295\\1.0295 is the mean value[/tex]

The number near the middle of the point is the median value. At the halfway point, there are two values.

[tex](1.001 + 1.011) / 2 = 1.006\\ 1.006 is the median value.[/tex]

As a result, the median value, which depicts the middle value of the numbers in the result, is less than the mean value, which depicts the real middle value of the numbers if they were equally distributed.

Their difference is that 1.0295 - 1.006 = 0.0235

1.397 observations make up the biggest sample. It may be made smaller by taking the number and removing the difference between the mean and median.

Consequently, there is a 0.0235-point difference between the mean and median.

Therefore;

[tex]1.397 - 0.0235 = 1.3735[/tex]

The median value won't change if the greatest sample Observation is decreased to 1.3735.

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