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a baseball approaches home plate at a speed of 44.0 m/s, moving horizontally just before being hit by a bat. the batter hits a pop-up such that after hitting the bat, the baseball is moving at 57.0 m/s straight up. the ball has a mass of 145 g and is in contact with the bat for 1.70 ms. what is the average vector force the ball exerts on the bat during their interaction? (let the x-direction be in the initial direction of motion, and the y-direction be up.)

Answer :

The average vector force the ball exerts on the bat during their interaction is 5151N.

Solution:

v = 57m/s

(v-u) = 55m/s -44m/s

(v-u)| = √(57m/s)² + (-44m/s)² = 71.06m/s V

dP = m (v-u) = 10.3kgm/s

F = dP/ dt = 5151N.

Average force is a vector quantity that has both magnitude and direction. During a certain time interval t, the force is expressed as a pulse change frequency. It is difficult to calculate the rate of change when the time interval is small. This is where the term average force comes into play.

The average force is equal to the mass of an object multiplied by the object's average velocity over a defined period of time. Average force is a force that is not constant but varies over time. There are nearly constant values ​​for calculating other relevant aspects. Net force, on the other hand, refers to the total force exerted on an object.

Learn more about  Average force here:- https://brainly.com/question/29646113

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