A hypothetical population of 200 cats has two alleles, T- and Te, for a locus that codes for tail length. The table below describes the phenotypes of cats with each possible genotype, as well as the number of individuals in the population with each genotype. Which statements about the population are true?(picture)Heterozygotes make up 20% of the population. Homozygotes make up 80% of the population. Homozygotes make up 30% of the population. In the entire cat population, 60% of the alleles are TS. In the entire cat population, the frequency of the allele is 0.5. In the entire cat population, the frequency of the allele is 0.4. Assurning random mating, each gamete has a 50% chance of having a hallele and a 50% chance of having a 7 allele. Assuming random mating, each gamete has a 40% chance of having a Tallele and a 60% chance of having a 7 allele.

Alleles T and Te make up the population's gene pool for tail length. The frequency of the T allele is 0.4 (160/400). This can also be stated as 40% of the alleles being T.

Te has a 0.6 allele frequency (240/400). The fact that 60% of the alleles are Te is another way to state this. Therefore, assuming random mating, each gamete (sperm or egg) has a 40% probability of carrying allele T and a 60% chance of having allele Te.

Heterozygotes make up 20% of the population, according to these statements.

80% of the population are homozygotes.

60% of the alleles in the cat population as a whole are Te.

The frequency of the T allele in the total cat population is 0.4.

Every gamete has a 40% probability of having a T allele and a 60% chance of having a Te allele, assuming random mating.

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