Answer :
A . The emitted particle is β⁻.
The radiactive isotope ¹³¹ I ₅₃ decays into ¹³⁵Xe₅₄ by emitting a beta particle and an information .
¹³¹ I ₅₃ --> ¹³⁵Xe₅₄+ β⁻ +v + Q
Therefore, The emitted particle is β⁻.
B .the energy Q released when 131 53I decays and 131 54 Xe is formed is 0.966MeV
Q= Δmc²
= (130.906118u - 130.90508u - 0.32*10⁻⁴u)(931.5MeV/c²)
= 0.966MeV
C . the decrease in mass, ΔmXe, of the xenon nucleus is 3.87*10⁻⁴ u.
= hc/λ
= [tex]\frac{(6.625*10^{-34} )(3*10^{8} m/s)}{3.44*10^{-12} }[/tex]
= 0.3605 MeVj
Δm = (0.3065)MeV([tex]\frac{1u}{931.5Mev/c^{2} }[/tex])
= 3.87*10⁻⁴ .
Mass is a quantitative measure of inertia in physics and a fundamental property of all matter. In effect, it is the resistance that an object offers to changes in velocity or position when a force is applied. The greater the mass of an object, the smaller the change caused by an applied force.
Mass can be experimentally defined as the inertia of a body, a measure of its resistance to acceleration (change in velocity) when a net force is applied. An object's mass also determines the strength of its attraction to other bodies. size. A 2kg cast iron weight used for scales. The decrease in mass, ΔmXe, of the xenon nucleus is 3.87*10⁻⁴ u
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