Premature Birth and Education Does the length of term of pregnancy play role in the level of education of the baby? Researchers Norway followed over million births between 1967 and 1988 and looked at the educational attainment of the children: The following data are dased the results of their research: Note that full-term pregnancy 38 weeks. gestational period independent of completing high school diploma? Use the 0.05 level of significance. Show five steps unnmen Perud (neeks) 21-27 272 W4J6 J7-2 4 04 Than Hih Ved Sbor [get 30n)

The length of pregnancy does play a role in the education level of the baby. A significant relationship can be established using the chi square test.

What is a chi square test?

A chi square ( χ2) test is performed in order to find a co relation between two unrelated variables. The main objective of the test is to prove whether the relationship holds true or is just a product of mere chance. For example, if we are conducting a survey of two different parameters, first being the population of people who are married and the other about their educational qualification, we will get two distinct table of values without any significant co relation. But now if we want to establish a relationship, lets say that married people have less educational qualifications, we need to prove our statement by performing a chi square test. The final value can either be a null hypothesis which states that their is no convincing relationship between the two parameters or can be a alternate hypothesis with significant co relation.

Using chi square for the problem:

Following data can be represented on tabular form and calculated:

Gestation Period (Observed)

22-27 28-32 33-36 37-42 43+ Tot

Less than high YES 14 34 140 1010 81 1279

school degree NO 26 65 343 3032 208 3674

40 99 483 4042 289 4953

Gestation Period (Expected)

YES 10.32 25.56 124.72 1043.75 74.62

NO 29.67 73.43 358.27 2998.24 214.37

χ2 = ∑ [tex]\frac{(Observed-Expected)^2}{Expected}[/tex]

= [tex]\frac{13.54}{10.32} +\frac{71.23}{25.56} +\frac{233.47}{124.72} +\frac{1139.06}{1043.75} +\frac{40.70}{74.62} +\frac{13.46}{29.67} +\frac{233.17}{358.27} +\frac{1139.73}{2998.24}+\frac{40.57}{214.37}[/tex]

= 1.31+2.78+1.87+1.09+0.54+0.45+0.96+0.65+0.38+0.18 = 10.21

Now, calculating the degree of freedom= (coulmn-1)(row-1)= (5-1)(2-1) = 4

Looking at the reference table at 0.05 significance level, the value is 9.488

As the calculated value is more than the table value/critical value, null hypothesis can be rejected proving the alternate hypothesis that there might be a relationship between gestation period of a mother and the education level of her kid.

For more information regarding chi square tests, follow the link: brainly.com/question/29415488

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