The reduced mass of H2 and N2 is 1.86g.
In Newtonian mechanics' two-body problem, the reduced mass is the "effective" inertial mass. It is a quantity that makes it possible to solve the two-body problem as if it were a one-body problem. However, the mass that determines gravitational pull is not lowered. It is denoted by μ.
It is given by equation:
1 / μ = 1 / m1 + 1 / m2
μ = [tex]\frac{m1 * m2}{m1 + m2}[/tex]
According to the question,
Molar mass of H2 = 2
Molar mass of N2 = 28
Substituting the values in equation:
μ = [tex]\frac{2 * 28}{2 + 28}[/tex]
μ = [tex]1.86 g[/tex]
The reduced mass of H2 and N2 is 1.86g.
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