Answer :
The reaction quotient of the reaction of the is obtained as 7.2 * 10^-2 while the cell potential is the cell is 1.93 V.
What is the reaction quotient?
We know that the reaction quotient has to do with the constant that shows the extent to which the reactants are converted into products under non equilibrium conditions. This implies under the conditions that are not covered by the equilibrium constant of the reaction.
Then we know that in the case of the reaction that we have;
Q = [tex][Mg^{2+} ][/tex]/[tex][Fe^{2+}][/tex]
Given that;
Iron II = 2.90 M
Magnesium ion = 0.210 M
Then;
Q = 0.210 M/2.90 M
Q = 7.2 * 10^-2
Now we obtain the Ecell from;
Ecathode - Eanode
We then have;
-0.44 V - (-2.37 V)
= 1.93V
The calculations show that the cell reaction quotient for the ions can be given as 7.2 * 10^-2 and the cell potential is 1.93 V.
Learn more about reaction quotient: https://brainly.com/question/24202150?