Draw the structure of the product of the reaction between the compound shown below and BF3. CH3SCH3 You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. If the reaction involves proton transfer, draw the products in separate sketchers. If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only.

Answer :

stereochemistry of triphenyl. Methyl benzoate with too much phenylmagnesium bromide engage in a Grignard reaction, which results in the formation of methanol.

In this situation, there will be a decrease response. From an ester group, we go on to an alcohol group. The LiAlH4 group must first transfer a hydride to the carbonyl group. After then, the ethyl group splits into ethanol and an aldehyde, which continue to interact with LiAlH4. In this instance, another hydride is transferred to the carbonyl group and alcohol is produced as a result. (See Figure. The stereochemical outcome of the Grignard reaction between excess phenylmagnesium bromide and methyl benzoate is triphenyl methanol. The reaction advances through a nucleophillic reaction as the carbonyl moiety is attacked. A tetrahedral structure is developing.

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