The speed of the bullet immediately after it exits the block is 190 m/s.
What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or even the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as that of the duration of the time interval gets closer to zero. The average speed of an object in a period of time is indeed the distance travelled by object divided by duration of the interval. Velocity and speed are not the same thing. The dimensions of speed are time divided by distance.
The speed immediately after the bullet exits the block is 190 m/s. This can be determined using the conservation of momentum principle, which states that the total momentum of an isolated system remains constant. In this case, the system is the bullet and the block of wood.
Before the bullet enters the block, the momentum of the system is equal to the momentum of the bullet, which is given by:
p_i = m_b * v_b = (3.0 g) * (520 m/s) = 1560 g m/s
After the bullet exits the block, the momentum of the system is equal to the momentum of the bullet and the block, which is given by:
p_f = m_b * v_b + m_w * v_w = (3.0 g) * (190 m/s) + (3.8 kg) * (0 m/s) = 570 g m/s
By conservation of momentum, we can set the initial and final momentum equal to each other and solve for the velocity of the bullet after it exits the block:
p_i = p_f
1560 g m/s = 570 g m/s + (3.8 kg) * v_w
v_w = 190 m/s
Therefore, the speed of the bullet immediately after exiting the block is 190 m/s.
To learn more about speed
https://brainly.com/question/13943409
#SPJ4
