A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A, B, C, and D). Four properties are randomly selected from each neighborhood and the ratios recorded for each, s shown below. A: 12, 11, 09, 0.4 C 1.0, 1.5, 1.1, 1.3 B: 2.3, 2.1,1.9, 1.6 D0.8,1.3, 1.1, 0.7 The ressults of the analysis are Sumarized in the following ANOVA table F P-value 1818 1.0606 Neighbarhood Error Total 0001 12 4.3644 (a) (Spt) Fill in the blanks in the ANOVA table. (Show your steps for partial credits (b) (2pt) Bsed on the P-value in the ANOVA, you should rejesct) Hp then conclude thnt (reject or not (c) (2pt) The realtor decided to compare the 4 population mes by using the a multiple comparison procedure. In this case, you prefer to uTukey or Bonferroni) because (d) (1pt) Given the multiple comparison procesdr comparisons that can be made in (c), there are

(c) Reject the null hypothesis since the test's p-value (0.001) is less than 0.05. One might draw the conclusion that there is evidence of a difference in the mean ratios for the 4 neighborhoods based on the sample data.

Given data,

A realtor wants to compare the mean sales-to-appraisal ratios of residential properties sold in four neighborhoods (A, B, C, and D). Four properties are randomly selected from each neighborhood ;

(a) The within-group sum of squares for this analysis will be

4.3644 - 3.1819 = 1.1825

Hence, within the group sum of squares for this analysis is 1.1825.

(b) There are four groups so df for within groups is 12 so the within-group mean squares for this analysis will be,

[tex]\frac{1.1825}{12}=0.0985[/tex]

(c) Since the p-value of the test (0.001) is less than 0.05, reject the null hypothesis. That is based on sample evidence one can conclude that there is evidence of a difference in the mean ratios for the 4 neighborhoods.

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