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Consider a container of volume 5.0dm3 that is dividedinto two compartments of equal size. In the left compartment thereis nitrogen at 1.0 atm and 25oC; in the rightcompartment there is hydrogen at the same temperature and pressure.Calculate teh entropy and Gibbs energy of mixing when the partitionis removed. Assumed that the gases are perfect.

Answer :

Gibbs energy of mixing when the partitionis removed is +0.47JK⁻¹.

Entropy is a measure of disorder in a system. It is also the number of possible ways that particles and their energy can be distributed in a system.

Gibbs free energy, denoted G, combines enthalpy and entropy into a single value. The change in free energy, ΔG, is equal to the sum of the enthalpy plus the product of the temperature and entropy of the system

ΔG= nRT (x, ln x, +x In x}[518] x=x=0.5, n= pv/ RT

=(-1.0)x(1.013×10' Pa)x(2.0×10' m')x(In 2) = 1.4 *10^2 = -0.14JK⁻¹

ΔS=-nR(x, Inx+x, Inx) [5.19] -0.14k = +0.47 JK

To know more about gibbs free energy:-

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