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the forearm in the figure(figure 1) accelerates a 3.2 kg ball at 7.5 m/s2 by means of the triceps muscle, as shown. a) Calculate the torque needed. Ignore the mass of the arm. Answer in m*Nb) Calculate the force that must be exerted by the triceps muscle. Answer in N

Answer :

The calculated answer for the torque is 7.812 Nm and the force is 25.2 N

In the given question, we have to find the torque needed and the force exerted by the triceps muscle.

We know that, when there is a net torque on the system, it causes angular acceleration and the angular momentum is no more conserved.

Here let be the arm is massless.

The torque can be written as

              τ=Iα

Where I is the moment of inertia.

α is the angular acceleration.

So,

  τ=mR^2 α

    τ=mRa

Here we have used the relationship between angular and tangential acceleration, which is: α=a/R.

The position vector is:  R = 0.31

The mass is:   m =3.6

The tangential acceleration is:   a =7 m/s2

So, the torque will be,

τ=3.6*0.31*7

  =7.812

So, the required torque is 7.812 Nm.

And we know that torque is:  τ=F.R

So,   force is F =  τ/r

 = 7.812/0.31

 =25.2 N

To know more about tangential acceleration, click the below link

https://brainly.com/question/14993737?referrer=searchResults

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