Answer :
The horizontal force applied on block E is 1343.89 lbs
Let [tex]E_{y}[/tex] and Eₓ are reactions and AD=d, now as ∑[tex]M_{A}[/tex]=0=D
[tex]E_{yx}[/tex]d = [tex]P_{x}[/tex]d=D[tex]E_{y}[/tex]=P=240lbs
BB'=a×sin15°
=1.035m
B'E=6×cos15°
now,∑[tex]M_{B}[/tex]=0
Eₓ×BB'=[tex]E_{y}[/tex]×B'E
Eₓ=240×5.795/1.035
Eₓ=1343.89 lbs
Any action that seeks to preserve, modify, or deform a body's motion is considered to be a force in mechanics. The concept of force is typically described in terms of Isaac Newton’s three laws of motion set forth in his Principia Mathematica (1687). (1687). Newton's first law states that until a force is applied to a body, it will remain in either its resting or uniformly moving state in a straight path. The second law indicates that when an external force acts on a body, it creates acceleration.
Learn more about force here:
https://brainly.com/question/14110395
#SPJ4