Answer :
Exactly 25.34 mL of 0.113 m bacl2 and 13.1 mL of sodium sulphate in solution of 0.218 m react. The inorganic substance sodium sulphate has the formula Na2SO4.
Number of milli moles of BaCl2 is equal to the molarity of BaCl2 times the volume of BaCl2 solution in mL, which is 0.113 M times 25.34 mL, or 2.86342 mmols.
Na2SO4 + BaCl2 = BaSO4 + 2NaCl
In light of the equation's balance,
The formula for calculating the amount of Na2SO4 needed is: Millimoles of BaCl2 X the volume of Na2SO4 solution in mL = 2.86342 mmols.
Needed volume of Na2SO4 solution divided by 0.218 M equals 2.86342 mmols.
Needed sodium sulphate solution volume: 13.1 mL
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The complete question is -
how many ml of 0.218 m sodium sulfate react with exactly 25.34 ml of 0.113 m bacl2 given the reaction: Na2SO4 + BaCl2 = BaSO4 + 2NaCl.