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A square loop of wire lies in the plane of the page and carries a current I as shown. There is a uniform magnetic field Vector B parallel to the side MK as indicated. The loop will tend to rotate: A. about PQ with KL coming out of the page B. about PQ with KL going into the page C. about RS with MK coming out of the page D. about RS with MK going into the page E. about an axis perpendicular to the page.

Answer :

The correct option A. about PQ with KL coming out of the page B; for the direction of the rotation of the loop for the uniform magnetic field.

Explain the term uniform magnetic field?

  • The field lines must be both parallel and equally spaced in order for the region under examination to have a uniform magnetic field, which must have the same strength and direction throughout.
  • If the magnetic field's lines are parallel, the magnetic field's intensity will be the same at every place, meaning the field's strength will be constant.

Assume that the X and Y axes are, respectively, along OQ and OR.

  • Since the current in MK is along B, F(MK) = 0.
  • Since the current in LN is the opposite of B, F(LN) = 0.

The two forces, F(KL) and F, have different lines of attack (MN).

The angle of perpendicularity between F(KL) and F(MN) is l.

As a result, the square loop will revolve around PQ, with KL emerging from the page.

To know more about the uniform magnetic field, here

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