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calculate the theoretical oxygen demand (in mg/l) of a solution containing 450 mg of glucose (c6h12o6) in 2 liters of distilled water. (hint: write and balance the oxidation reaction of glucose) (4 pts)

Answer :

The theoretical oxygen demand THOD=239.792 mg/L is given for the solution of 450 mg of glucose.

Theoretical Oxigen demand (THOD):

is the theoretical quantity of oxygen

required to oxidize the natural fraction of a

waste as much as carbon dioxide and water.

  • → Csln = 450 mg C6H12O6 / 2 L H2O =
  • 225 mg/L sln
  • .. mm C6H12O6 = 180.156 g/mol
  • balanced reaction:
  • C6H12O6+ 602 6CO2 + 6H2O mol C6H12O6 = 1 mol
  • → mass C6H12O6 (180.156 g/mol)(1 mol) = =
  • 180.156 g
  • The fee of ThOD is decided when
  • 180.156 g C6H12O6 devour mass O2 =.mm C6H1206 = 180.156 g/mol
  • balanced reaction:
  • C6H12O6+6O2 6CO2+6H2O mol C6H12O6 = 1mol
  • Rightarrow massC6H12O6 = (180.156g / m * ol)(1mol) = 180.156 g
  • he fee of ThOD is decided when
  • 180.156 g C6H12O6 devour mass 02 =
  • 6(32) = 192 g Oxygen; then in an answer of
  • 225mg / L you have: → ThOD = (192/180.156)x 225mg / L
  • ThOD = 239.792mg / L.

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