- The critical value for this test is of: t = ±1.7109.
- The test statistic for this test is of: t = -4.
How to obtain the critical value for the test?
We have a two-tailed test, as we are testing if the mean is different of a value.
The t-distribution is used, as we have the standard deviation for the sample, and the parameters are given as follows:
- 25 - 1 = 24 degrees of freedom.
- Significance level of 0.10.
Using a t-distribution calculator, the critical value is of:
t = ± 1.7109.
How to obtain the test statistic?
The equation for the test statistic is defined as follows:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
The parameters are:
- [tex]\overline{x}[/tex] is the sample mean.
- [tex]\mu[/tex] is the value tested at the null hypothesis.
- s is the standard deviation of the sample.
In the context of this problem, the values of these parameters are of:
[tex]\overline{x} = -34.3, \mu = 0, s = 42.9, n = 25[/tex]
Hence the value of the test statistic is of:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{-34.3 - 0}{\frac{42.9}{\sqrt{25}}}[/tex]
t = -4.
More can be learned about the test of an hypothesis at https://brainly.com/question/13873630
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