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suppose that you and a friend are playing cards and decide to make a bet. if your friend draws two non-face cards, where a face card is a jack, a queen, or a king, in succession from a standard deck of 52 cards replacing the first card, you give him $30. otherwise, he pays you $50. if the same bet was made 20 times, how much would you expect to win or lose? round your answer to the nearest cent, if necessary.

Answer :

I will win about $ 59.

This is a question of permutations and combinations.

We know that,

Probability of getting two non face cards = [tex]\frac{^{40}C_2}{{^{52}C_2}}[/tex] = 10/17

Probability of not getting two non face cards = 1 - (10/17) = 7/17

Hence, we can write,

Money I will get = (7/17)*50*20 =  $ 411.764

Money I'll have to pay = (10/17)*30*20 = $ 352.94

We know that,

Money left with me = Money I will get - Money I'll have to pay

Hence, we can write,

Money left with me =   $ 411.764 - $ 352.94

Money left with me =  58.824 ≈ $ 59

To learn more about Probability, here:-

https://brainly.com/question/11234923

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