Answered

four identical red balls and two identical black balls are placed in a box. one ball is randomly selected. without replacement, the second ball is selected. what is the probability that at least one of the balls is red.

Answer :

The probability that atleast one ball is red is 14/15.

Given that:-

Number of red balls = 4

Number of black balls = 2

One ball is randomly selected, without replacement, the second ball is selected.

We have to find the probability that atleast one ball is red.

There are four ways in which this can happen:-

RR, BR, RB, BB

Where R stands for Red ball and,

B stands for Black ball.

We know that,

Probability that no ball is red + Probability that atleast one ball is red = 1

Hence, we can write,

Probability that atleast one ball is red = 1 - Probability that no ball is red

P(BB) = (2/6)*(1/5) = 1/15

Hence,

Probability that atleast one ball is red = 1 - (1/15) = 14/15

To learn more about  probability, here:-

https://brainly.com/question/11234923

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