A circle has a center at (3,-2) and a radius of 5.Create the equation of the the circle:(x2+ (y)2 =IIWord Bank:2 10 +2 25 +3 5 -3Blank 1:Blank 2:Blank 3:

A Circle Has A Center At 32 And A Radius Of 5Create The Equation Of The The Circlex2 Y2 IIWord Bank2 10 2 25 3 5 3Blank 1Blank 2Blank 3 class=

Answer :

Given a circle with a center at (3,-2) and a radius of 5. We can create the equation of the circle using the formula below;

[tex](x-a)^2+(y-b)^2=r^2[/tex]

x =x coordinate of circle point

a=x coordinate of the center point = 3

y=y coordinate of circle point

b=y coordinate of the center point =-2

r=radius of the circle = 5

We would then substitute the given values in the equation above;

[tex]\begin{gathered} (x-3)^2+(y-(-2))^2=5^2 \\ (x-3)^2+(y+2)^2=25 \end{gathered}[/tex]

From the solution, we can proceed to fill in the blanks

ANSWER:

Blank 1: -3

Blank 2: +2

Blank 3: 25