A circle has a center at (3,-2) and a radius of 5.Create the equation of the the circle:(x2+ (y)2 =IIWord Bank:2 10 +2 25 +3 5 -3Blank 1:Blank 2:Blank 3:

Given a circle with a center at (3,-2) and a radius of 5. We can create the equation of the circle using the formula below;
[tex](x-a)^2+(y-b)^2=r^2[/tex]x =x coordinate of circle point
a=x coordinate of the center point = 3
y=y coordinate of circle point
b=y coordinate of the center point =-2
r=radius of the circle = 5
We would then substitute the given values in the equation above;
[tex]\begin{gathered} (x-3)^2+(y-(-2))^2=5^2 \\ (x-3)^2+(y+2)^2=25 \end{gathered}[/tex]From the solution, we can proceed to fill in the blanks
ANSWER:
Blank 1: -3
Blank 2: +2
Blank 3: 25