Hi, can you help me answer this question please, thank you

-1.010
The formula for calculating the test statistics is expressed as:
[tex]t=\frac{\frac{\overline{x}-\mu}{\sigma}}{\sqrt[]{n}}[/tex]Given the following parameters
Mean x = 6.2
Standard deviation σ = 3.43
μ = 6.7
n = 48
Substitute the given parameters into the formula:
[tex]\begin{gathered} t=(\frac{\frac{6.2-6.7}{3.43}}{\sqrt[]{48}}) \\ t=\frac{-0.5}{0.495077} \\ t=-1.0099 \\ t=-1.010 \end{gathered}[/tex]This shows that the test statistics rounded to 3 decimal places is -1.010