A recent math test had an average score of 75, with a standard deviation of 10. What percentage of people passed the test (i.e. scored a 70 or higher)?

A Recent Math Test Had An Average Score Of 75 With A Standard Deviation Of 10 What Percentage Of People Passed The Test Ie Scored A 70 Or Higher class=
A Recent Math Test Had An Average Score Of 75 With A Standard Deviation Of 10 What Percentage Of People Passed The Test Ie Scored A 70 Or Higher class=

Answer :

We have to find the z-score at first, then use it to find the percentage of 70 or higher

The rule of the z-score is

[tex]z=\frac{x-\mu}{\sigma}[/tex]

μ is the mean

σ is the standard deviation

Since the average score is 75, then

[tex]\mu=75[/tex]

Since the standard deviation is 10, then

[tex]\sigma=10[/tex]

Since we need the percentage of 70, then

[tex]x=70[/tex]

Substitute them in the rule above to find z

[tex]\begin{gathered} z=\frac{70-75}{10} \\ z=-\frac{5}{10} \\ z=-0.5 \end{gathered}[/tex]

Now, we will search in the table for the value of -0.5

The value of -0.5 is 0.30854

Since we need the percentage of 70 or higher, then

[tex]\begin{gathered} P(x\ge70)=1-P(x) \\ P(x\ge70)=1-0.30854 \\ P(x\ge70)=0.69146 \end{gathered}[/tex]

Change it to percent

[tex]\begin{gathered} P(x\ge70)=0.69146\times100\text{ \%} \\ P(x\ge70)=69.146\text{ \%} \end{gathered}[/tex]

The percentage of 70 or higher is about 69.15%