Solution:
Given the equation:
[tex]\begin{gathered} y=2650(1.05)^x \\ where \\ x\text{ is the number of years invested } \\ y\text{ is the value in dollars} \end{gathered}[/tex]To determine the value of the investment after 25 years, we have
[tex]\begin{gathered} y=2650(1.05)^{25} \\ =2650\times(1.05)^{25} \\ =8973.84059 \\ \\ \Rightarrow y\approx\$8974\text{ \lparen nearest dollar\rparen} \end{gathered}[/tex]Hence, to the nearest dollar, we have the value of the investment to be
[tex]\$\text{8974}[/tex]The correct option is