Hello!
Let's write the equation below in the slope-intercept form y = mx -b:
[tex]y-3=\frac{1}{2}(x-6)[/tex]
Isolating y, we will have:
[tex]\begin{gathered} y=\frac{1}{2}(x-6)+3 \\ \\ y=\frac{1}{2}x\cancel{-3}\cancel{+3} \\ \\ \boxed{y=\frac{1}{2}x+0} \end{gathered}[/tex]
As we have it in the slope-intercept form, it's easier to find the value of b.
As we can see:
m = 1/2
b = 0
