Answer :
Input data
A = (5, -6)
[tex]7x-12y=5[/tex]Procedure
First we must determine the slope of the straight line to make it parallel
[tex]y=\frac{7}{12}x-\frac{5}{12}[/tex]The slope of the straight line would be m = 7/12
[tex]\begin{gathered} b=y-mx \\ b=-6-\frac{7}{12}\cdot5 \\ b=-6-\frac{35}{12} \\ b=-\frac{72}{12}-\frac{35}{12} \\ b=-\frac{107}{12} \end{gathered}[/tex]The equation of the line that passes through the point (5,-6) with a slope of 7/12 is
[tex]y=\frac{7}{12}x-\frac{107}{12}[/tex]