Answer :
We are given the following information:
[tex]\begin{gathered} \text{Let the first integer be represented as ''x''} \\ \text{Let the second integer be represented as ''x+1''} \\ \text{Let the third integer be represented as ''x+2''} \\ \text{The sum of the 3 integers is given by:} \\ x+x+1+x+2=-17 \\ 3x+3=-17 \\ \text{Subtract ''3'' from both sides, we have:} \\ 3x=-17-3 \\ 3x=-20 \\ \text{Divide both sides by ''3'', we have:} \\ x=-\frac{20}{3} \\ x=-6\frac{2}{3} \\ x+1=-5\frac{2}{3} \\ x+2=-4\frac{2}{3} \end{gathered}[/tex]The value of ''x'' is not an integer.
This, therefore, means that there is no true solution to the question