From the given question we can extract all the necessary parameters to enable us to find the solution to the question.
We would therefore have the following parameters
[tex]\begin{gathered} \text{observed }value=X=299 \\ S\tan darddeviation=\sigma=43 \\ \text{sample}=n=8 \\ \text{average}=\mu=272 \end{gathered}[/tex]This would be inserted into the formula given for the z score below
[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt[]{n}}}[/tex]This would then be written as
[tex]\begin{gathered} z=\frac{299-272}{\frac{43}{\sqrt[]{8}}} \\ z=1.78 \end{gathered}[/tex]We look up the z score on the probability table to get 0.9625. We then subtract from 1 to get the answer
[tex]p(z>1.78)=0.0375[/tex]ANSWER=0.0375