Answer :
,,Given The expression below
[tex]16y^2-24y+9[/tex]To Factor the given perfect square trinomial
[tex]\begin{gathered} product=9\times16y^2=144y^2 \\ sum=-24y \end{gathered}[/tex]Substitute the the sum with two factors of the product
The factors to replace the sum are
[tex]\begin{gathered} -12y\times-12y=144y^2 \\ -12y-12y=-24y \end{gathered}[/tex]Replace the sum with the factors
[tex]\begin{gathered} 16y^2-12y-12y+9 \\ 4y(4y-3)-3(4y-3) \\ (4y-3)(4y-3) \end{gathered}[/tex]Hence
16y²-24y+9 = (4y-3)(4y-3) = (4y-3)²