Use the graph of h(x)=1-3x/x-1and its asymptotes to find the following limits.If necessary, choose the most informative answer from

Solution
For this case we have the following function:
[tex]h(x)=\frac{1-3x}{x-1}[/tex]And we can find the following:
[tex]\lim _{x\to-\infty}h(x)=-3[/tex][tex]\lim _{x\to\infty}h(x)=-3[/tex]